string boolEnable = "True";

Then you need to ask yourself: Performance or memory efficiency? Is it worth the extra cycles and instructions to put 8 bools in one byte and & 0x bitmask the relevant one?

I set all 8 bits to 1 because I want it to be really true.

Depending on the language

typedef struct {
    bool a: 1;
    bool b: 1;
    bool c: 1;
    bool d: 1;
    bool e: 1;
    bool f: 1;
    bool g: 1;
    bool h: 1;
} __attribute__((__packed__)) not_if_you_have_enough_booleans_t;

In the industrial automation world and most of the IT industry, data is aligned to the nearest word. Depending on architecture, that’s usually either 16, 32, or 64 bits. And that’s the space a single Boolean takes.

I have a solution with a bit fields. Now your bool is 1 byte :

struct Flags {
    bool flag0 : 1;
    bool flag1 : 1;
    bool flag2 : 1;
    bool flag3 : 1;
    bool flag4 : 1;
    bool flag5 : 1;
    bool flag6 : 1;
    bool flag7 : 1;
};

Or for example:

struct Flags {
    bool flag0 : 1;
    bool flag1 : 1:
    int x_cord : 3;
    int y_cord : 3;
};

Back in the day when it mattered, we did it like

#define BV00		(1 <<  0)
#define BV01		(1 <<  1)
#define BV02		(1 <<  2)
#define BV03		(1 <<  3)
...etc

#define IS_SET(flag, bit)	((flag) & (bit))
#define SET_BIT(var, bit)	((var) |= (bit))
#define REMOVE_BIT(var, bit)	((var) &= ~(bit))
#define TOGGLE_BIT(var, bit)	((var) ^= (bit))

....then...
#define MY_FIRST_BOOLEAN BV00
SET_BIT(myFlags, MY_FIRST_BOOLEAN)

if wasting a byte or seven matters to you, then then you need to be working in a lower level language.

just like electronic components, they sell the gates by the chip with multiple gates in them because it’s cheaper

Redundancy is nice in the event of bitflip errors